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2m^2-2=144
We move all terms to the left:
2m^2-2-(144)=0
We add all the numbers together, and all the variables
2m^2-146=0
a = 2; b = 0; c = -146;
Δ = b2-4ac
Δ = 02-4·2·(-146)
Δ = 1168
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1168}=\sqrt{16*73}=\sqrt{16}*\sqrt{73}=4\sqrt{73}$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{73}}{2*2}=\frac{0-4\sqrt{73}}{4} =-\frac{4\sqrt{73}}{4} =-\sqrt{73} $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{73}}{2*2}=\frac{0+4\sqrt{73}}{4} =\frac{4\sqrt{73}}{4} =\sqrt{73} $
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